Mercurial
annotate asyncio_threads/frontend/longest_subinteger.py @ 71:75de5903355c
Giagantic changes that update Dowa library to be more align with stb style array and hashmap. Updated Seobeo to be caching on server side instead of file level caching. Deleted bunch of things I don't really use.
| author | June Park <parkjune1995@gmail.com> |
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| date | Sun, 28 Dec 2025 20:34:22 -0800 |
| parents | 46daba6e3cf4 |
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| rev | line source |
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Few python scrtips to show how to use asychio.
MrJuneJune <me@mrjunejune.com>
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1 # Analyze a given array of integers and write a function to determine the length of the longest subsequent growing sequence contained within the array. |
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2 |
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3 |
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4 # 1,2,3,4,2,1,3 |
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5 # | |
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6 |
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7 # Example 1: |
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8 # |
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9 # Input: nums = [10,9,2,5,3,7,101,18] |
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10 # [(2, 1), 3, 5, 7, 9, 10, 18, 101] |
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11 # | |
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12 # Output: 4 |
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13 |
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14 # Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4. |
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15 |
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16 # Example 2: |
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17 # |
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18 # Input: nums = [0,1,0,3,2,3] |
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19 # Output: 4 |
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20 # Example 3: |
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21 # |
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22 # Input: nums = [7,7,7,7,7,7,7] |
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23 # Output: 1 |
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24 |
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25 |
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26 # Longest Increasing Subsequence |
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27 def main(nums): |
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28 ans = 0 |
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29 cache = set() |
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30 |
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31 def dfs(val, pos, curr_ans): |
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32 nonlocal ans |
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33 |
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34 if ((val, pos, curr_ans) in cache): |
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35 return |
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36 |
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37 if pos > len(nums): |
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38 return |
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39 if nums[pos] > val: |
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40 curr_ans += 1 |
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41 else: |
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42 ans = max(ans, curr_ans) |
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43 return |
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44 for i in range(pos, len(nums)): |
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45 dfs(nums[pos], i, curr_ans) |
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46 |
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47 for i in range(len(nums)): |
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48 dfs(float("-inf"), i, 0) |
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49 |
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50 return ans |
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51 |
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52 |
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53 print(main([10,9,2,5,3,7,101,18])) |